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Question

Physics Question on Surface tension

Eight drops of mercury of equal radii combine to form a big drop. The capacitance of a bigger drop as compared to each smaller drop is

A

2 times

B

8 times

C

4 times

D

16 times

Answer

2 times

Explanation

Solution

CB=n13CSC_{B}=n^{\frac{1}{3}} C_{S}
CB=813CSC_{B}=8^{\frac{1}{3}} C_{S}
CB=2CSC_{B}=2 C_{S}