Question

Eight charges, each of the magnitude q are placed at the vertices of a cube placed in vacuum. Electric potential at the centre of the cube due to this system of charges is -

(e₀ is permittivity of vacuum and a is length of the each side of the cube)

• A. $\frac{2q}{\pi\varepsilon_{0}a}$
• B. $\frac{4q}{\sqrt{3}\pi\varepsilon_{0}a}$
• C. Zero
• D. $\frac{\sqrt{3}q}{\pi\varepsilon_{0}a}$

Answer 1

Answer: (B)

$\frac{4q}{\sqrt{3}\pi\varepsilon_{0}a}$

Answer 2

V_­centre = =

= $\frac { 4 q } { \pi \varepsilon _ { 0 } \mathrm { a } \sqrt { 3 } }$