Question

Eight charges, each of magnitude q are placed at the vertices of a cube placed in vacuum. Electric potential at the centre of the cube due to this system of charges is :

(e₀ is permittivity of vacuum and a is length of each side of the cube)-

• A. $\frac{2q}{\pi\varepsilon_{0}a}$
• B. $\frac{4q}{\sqrt{3}\pi\varepsilon_{0}a}$
• C. Zero
• D. $\frac{\sqrt{3}q}{\pi\varepsilon_{0}a}$

Answer 1

Answer: (B)

$\frac{4q}{\sqrt{3}\pi\varepsilon_{0}a}$

Answer 2

V_centre = $\frac { \mathrm { k } _ { \mathrm { Total } } } { \mathrm { r } }$ = $\frac { 1 } { 4 \pi \varepsilon _ { 0 } }$ $\frac { ( 8 q ) } { \left( \frac { a \sqrt { 3 } } { 2 } \right) }$ =