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Question

Mathematics Question on permutations and combinations

Eight chairs are numbered 1 to 8. Two women and three men wish to occupy one chair each. First the women choose the chairs from amongst the chairs marked 1 to 4 and then the men select the chairs from amongst the remaining. The number of possible arrangements is

A

6C3×4C2^6C_3 \, \times \, ^4C_2

B

4P2×4P3^4P_2 \, \times \, ^4P_3

C

4C2×4P3^4C_2 \, \times \, ^4P_3

D

None of these

Answer

None of these

Explanation

Solution

Since, the first 2 women select the chairs amongst 1 to 4 in 4P2^4P_2 ways. Now, from the remaining 6 chairs, three men could be arranged in 6P3^6P_3
\therefore Total number of arrangements = 4P2×6P3^4P_2 \, \times \, ^6P_3