Question

Effective atomic number of Fe in the complex $K_4[Fe(CN)_6]$ is

• A. 24
• B. 12
• C. 36
• D. 18

Answer 1

Answer: (C)

36

Answer 2

In $K_4[Fe(CN)_6]$ E.A.N. of Fe = Z-O .N . + 2 $\times$ C.N. = 26- 2 + 2 $\times$ 6 = 36