Question

Eccentricity of the hyperbola conjugate to the hyperbola $\frac{x^{2}}{4} - \frac{y^{2}}{12} = 1$ is:

• A. $\frac{2}{\sqrt{3}}$
• B. 2
• C. $\sqrt{3}$
• D. $\frac{4}{3}$

Answer 1

Answer: (A)

$\frac{2}{\sqrt{3}}$

Answer 2

$\frac{4}{12}$= e² –1

e² = 4/3

e =2/$\sqrt{3}$