Question
Question: Each side of a cube is measured to be \(7.203m\). The volume of the cube to appropriate significant ...
Each side of a cube is measured to be 7.203m. The volume of the cube to appropriate significant figure is:
(A) 31.3m3
(B) 313m3
(C) 373.7m3
(D) 37.3m3
Solution
Hint The volume of a cube is given by (side)3. The number of significant digits of the product of two or more numbers, is equal to the number of significant digits of a multiplied number, with minimum significant digits.
Complete step by step answer
We know that the volume of a cube is given by (side)3.
In this problem, it is given that side of the cube is 7.203m.
So, we can calculate the volume of the given cube as
V=(7.203)3
⇒V=373.7147544m3
Looking at this volume, you may get an idea of why significant numbers are important. It is meaningless to have so many numbers after the decimal. For practical use, it is always preferable to consider up to 2nd or 3rd decimal.
Now, we look into the number we first multiplied, i.e. 7.203.
This number has 4 significant numbers.
So, according to the rules of significant digits, the product of two or more numbers should have as many significant digits as the number with a minimum of significant digits.
In this problem, we are multiplying the same number i.e. 7.203. This number has 4significant digits.
So we need the product with 4significant digits.
So, rounding off the calculated volume up to 4 significant digits, we get
V=373.7m3
Thus, Option (C) is correct.
Additional Information If we have two numbers, 5.601 and2.34. The product of these two numbers will have 2 significant digits. However, for addition or subtraction, we consider the number with the highest number of significant digits. So the result of the addition of these two numbers will have 3significant digits.
Note: Don’t round off the number before multiplication, addition, or any arithmetic operation. It will give you the wrong answer. While rounding off the answer, be sure to follow the rules of rounding off a number to get a correct answer.