Question

Each capacitor shown in figure is $2\mu F$ . Then the equivalent capacitance between A and B is

• A. $2\mu F$
• B. $4\mu F$
• C. $6\mu F$
• D. $8\mu F$

Answer 1

Answer: (A)

$2\mu F$

Answer 2

Equivalent capacitance of upper arms in series ${{C}_{1}}=\frac{2\times 2}{2+2}=1\mu F$ In lowers arms ${{C}_{2}}=1\mu F$ Now ${{C}_{1}}$ and ${{C}_{2}}$ are in parallel $\therefore$ Equivalent capacitance $C={{C}_{1}}+{{C}_{2}}=2\,\mu F$