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Question: \(Eº\) values of three metals are listed below. \[Zn_{(aq)}^{2 +} + 2e^{-} \rightarrow Zn_{(s)};Eº ...

EºEº values of three metals are listed below.

Zn(aq)2++2e−→Zn(s);Eº=−0.76VZn_{(aq)}^{2 +} + 2e^{-} \rightarrow Zn_{(s)};Eº = - 0.76V

Fe(aq)2++2e−→2Fe(s);Eº=−0.44VFe_{(aq)}^{2 +} + 2e^{-} \rightarrow 2Fe_{(s)};Eº = - 0.44V

Sn(aq)2++2e−→Sn(s);Eº=−0.14VSn_{(aq)}^{2 +} + 2e^{-} \rightarrow Sn_{(s)};Eº = - 0.14V

Which of the following statement are correct on the basis of the above information?

(i) Zinc will be corroded in preference to iron if zinc coating is broken on the surface.

(ii) If iron is coated with tin and the coating is broken on the surface then iron will be corroded.

(iii) Zinc is more reactive than iron but tin is less reactive than iron.

A

(i) and (ii)

B

(ii) and (iii)

C

(i), (ii) and (iii)

D

(i) and (iii)

Answer

(i), (ii) and (iii)

Explanation

Solution

Iron coated with zinc does not get rusted even if cracks appear on the surface because Zn will take part in redox reaction not Fe as Zn is more reactive than Fe. If iron is coated with tin and cracks appear on the surface Fe will take part in redox reaction because Sn is less reactive than Fe.