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Question

Chemistry Question on Electrochemical Cells

EoE^{o} for Fe2++2eFeF e^{2+}+2 e^{-} \rightarrow F e is 0.44-0.44 volt and EoE^{o} for Zn2++2eZnZ n^{2+}+2 e^{-} \rightarrow Z n is 0.76-0.76 volt thus:

A

ZnZn is more electropositive than FeFe

B

ZnZn is more electronegative than FeFe

C

FeFe is more electropositive than ZnZn

D

none

Answer

ZnZn is more electropositive than FeFe

Explanation

Solution

High value for Ered oE_{\text {red }}^{o}. shows more electro negativity i.e., ZnZ n is more electropositive than FeFe. (EZn2+/Zno<EFe2+/Feo)\left(E^{o}_{Z n^{2+} / Z n}< E_{F e^{2+} / F e}^{o}\right)