Question

$e = \alpha t - \frac{1}{2}\beta t^{2}$, If temperature of cold junction is $0^{o} ⥂ C$ then temperature of inversion is$(\text{if }\alpha = 500.0\mu V ⥂ / ⥂^{o}C,\beta = 5.0\mu V ⥂ / ⥂ \text{Squar}\text{e}^{o}C$)

• A. 100
• B. 200
• C. 300
• D. 400

Answer 1

Answer: (B)

200

Answer 2

$t_{n} = \frac{\alpha}{\beta} = \left( \frac{500}{5} \right) = 100{^\circ}C$

Also $t_{n} = \frac{t_{i} + t_{c}}{2} \Rightarrow 100 = \frac{t_{i} + 0}{2}$⇒ $t_{i} = 200{^\circ}C$