Question
Chemistry Question on Electrochemistry
E=cr3+/cr0=−0.72V,Efe2+/fe0=−0.42 The potential for the cell Cr|Cr3+(0.1 M) || Fe2+(o.01 M) Fe is
A
-0.339 V
B
-0.26 V
C
0.26 V
D
0.3 V
Answer
0.26 V
Explanation
Solution
The correct option is (C): 0.26 V