Question

During the placement season of a class, 21 students got shortlisted for company A, 26 got shortlisted for Company B and 29 got shortlisted for company C and 14 students got shortlisted for both A and B,12 students got shortlisted for A and C and 15 for both B and C. All the companies shortlisted 8 students from the class. Then what is the ratio of number of students who got shortlisted for only B and number of students who got shortlisted for only C?

• A. 1:1
• B. 1:2
• C. 2:3
• D. 3:2

Answer 1

Answer: (B)

1:2

Answer 2

Let the number of students who got shortlisted for all three companies be $x$.
Using the principle of inclusion and exclusion for the total number of students shortlisted:
$21 + 26 + 29 - 14 - 12 - 15 + x = \text{Total students shortlisted}$
$21 + 26 + 29 - 14 - 12 - 15 + x = 8$
$35 + x = 8$
$x = 8 - 35$
$x = -27$
There seems to be a mistake in the total count or problem constraints. Based on the final expected total, let's reconsider without exclusions affecting directly.
To find the number of students shortlisted only for Company B and Company C, let's denote:
- Only B: $B - (A \cap B) - (B \cap C) + (A \cap B \cap C)$
- Only C: $C - (A \cap C) - (B \cap C) + (A \cap B \cap C)$
From the given:
- Shortlisted for B only = $26 - 14 - 15 + 8 = 5$
- Shortlisted for C only = $29 - 12 - 15 + 8 = 10$
Thus the ratio is:
$\frac{5}{10} = 1:2$
Answer: B 1:2