Question
Question: During the first half of the motion, applied force transfers more energy to the 
Complete step by step answer:
From x=0 to x=xmax
K.E=0
Applying the work-energy theorem between x=0 to x=xmax
W1+W2=0
⇒Fxmax+21 k(02−xmax2)=0
⇒xmax=k2F
So the first half is concerned with 0⩽x⩽kF
At, x=kF
U1= The potential energy = Energy stored in the spring = 21k(kF)2=2kF2
The kinetic energy At, x=kF is K1.
To calculate this we again apply the work-energy theorem between x=0 to x=kF
⇒W1+W2=K1−0
⇒F×kF+21 k[02−(kF)2]=K1
⇒kF2−2kF2=K1
⇒K1=2kF2
∴K1=U1
So, we get that the kinetic energy is equal to the stored energy or potential energy at the first half of the motion.
Hence, the right answer is in option C.
Note: Potential energy is energy that keeps – or preserved - in an object or substance. This keeps energy relies on the position, arrangement, or state of the item or substance. Spring P.E. may be a variety of hold on energy, very similar to gravitational P.E. or electrical P.E., one related to springs and elastic objects. The kinetic energy compressed the spring that has been changed into P.E.. After we leave the spring, the hold on P.E. is changed into kinetic energy.