Chemistry Question on Some basic concepts of chemistry

Question

During the conversion of $NH _{2} OH \rightarrow N _{2} O$ , the equivalent weight of $NH _{2} OH$ (mol. wt. of $NH _{2} OH$ is $M$ ) is

Answer 1

Solution

$\overset{-1}{NH _{2}} OH \longrightarrow \overset{+1}{N _{2}} O$
Conversion factor, $n =+1-(-1)$
$=+2$
Equivalent wt. of $NH _{2} OH$
$=\frac{\text { molecular weight }}{\text { conversion factor }}$
$=\frac{M}{2}$