Solveeit Logo

Question

Question: During take-off a jet airplane of mass \[10000\text{ kg}\] can produce a maximum thrust of \(40\text...

During take-off a jet airplane of mass 10000 kg10000\text{ kg} can produce a maximum thrust of 40 kN40\text{ kN}. At the point of take-off, the plane experiences a drag force of 20 kN20\text{ kN}.
a. Calculate the initial acceleration of the plane.
b. Calculate the acceleration of the plane at the point of take-off.

Explanation

Solution

To solve this question we will use our knowledge of Newton’s laws of motion specifically the Newton’s second law of motion. Newton's second law of motion states that the rate of change of momentum of a body is directly proportional to the force applied on it.

Complete step by step answer:
According to Newton’s second law of motion, the force acting on a body is directly proportional to the mass of the body and the acceleration of the body. Hence if we write it in the form of an equation, we would get:
F=maF=ma
Where FF is the force acting on the body,
mm is the mass of the body,
And aa is the acceleration of the body.
a. Now to calculate the initial acceleration of the plane we would rearrange the above formula as:
a=Fma=\dfrac{F}{m}
It is given that the maximum thrust produced by the jet airplane initially is F=40000 NF=40000\text{ N} and the mass of the jet airplane is given as m=10000 kgm=10000\text{ kg}.
On substituting the values in the equation, we would get:
a=4000010000 a=4 ms2 \begin{aligned} & a=\dfrac{40000}{10000} \\\ & \therefore a=4\text{ m}{{\text{s}}^{-2}} \\\ \end{aligned}
b. Now in the second part we need to calculate the acceleration of the plane at the point we need to take in consideration the drag force experienced by the jet airplane. Thus, the net force experienced by the jet airplane will be as follows:
F=(4000020000) N F=20000 N \begin{aligned} & F=\left( 40000-20000 \right)\text{ N} \\\ & \Rightarrow F=20000\text{ N} \\\ \end{aligned}
The acceleration of the plane at the point of take-off will be:
a=2000010000 a=2 ms2 \begin{aligned} & a=\dfrac{20000}{10000} \\\ & \therefore a=2\text{ m}{{\text{s}}^{-2}} \\\ \end{aligned}

Note: Newton’s second law of motion is the most important law because it quantitatively describes the force. It can be written in different forms. It can be written in terms of rate of change of momentum of a body or the acceleration of the body. Both of these mean the same thing.