During electrolysis of NaOH | Chemistry | SolveeIt

During electrolysis of NaOH

$H_2$ is liberated at cathode

$O_2$ is liberated at cathode

$H_2$ is liberated at anode

$O_2$ is liberated at anode.

Answer

$O_2$ is liberated at anode.

Explanation

During electrolysis of $NaOH$ (molten), $O_2$ if liberated at anode. $4OH^- {->} 2H_2O + O_2 + 4e^-$

Chemistry Question on Electrochemistry