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Question: During electrolysis of a solution of \(AgNO_{3},9650\)coulombs of charge is passed through the solut...

During electrolysis of a solution of AgNO3,9650AgNO_{3},9650coulombs of charge is passed through the solution. What will be the mass of silver deposited on the cathode?

A

108g108g

B

10.8g10.8g

C

1.08g1.08g

D

216 g

Answer

10.8g10.8g

Explanation

Solution

Ag++e1FAg108gAg^{+} + \underset{1F}{e^{-}} \rightarrow \underset{108g}{Ag}

Amount of Ag deposited by 9650 C

=10896500×9650=10.8g= \frac{108}{96500} \times 9650 = 10.8g