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Question

Chemistry Question on Thermodynamics

During compression of a spring the work done is 10kJ10\,kJ and 2kJ2\,kJ escaped to the surroundings as heat. The change in internal energy, ΔU(inkJ)\Delta\, U(in\,kJ) is:

A

8

B

12

C

-12

D

-8

Answer

8

Explanation

Solution

ΔU=q+w\Delta U = q + w q=2kJ,W=10kJq = - 2\,kJ, W = 10\,kJ ΔU=8kJ\Delta U = 8\,kJ