Question
Question: During an experiment an ideal gas is found to obey an additional law \[V{P^2} = \] constant. The gas...
During an experiment an ideal gas is found to obey an additional law VP2= constant. The gas is initially at temperature T and volume V, when it expand to volume 2V, the resulting temperature is T2:
A. 2T B. 2T C. 2T D. 2T
Solution
Here, we will use the law of ideal gas. That is PV=nRT where P is pressure, V is volume, n is the present number of moles of gas, R is ideal gas constant and T is the temperature. Then by using the given condition and finding the correlation between the two, will find the required change in Temperature.
Complete step by step answer:
Let, the initial volume be =V
The initial temperature be =T
The final volume be =2V
The final temperature be =T2
Now, by using the law of ideal gas equation –
PV=nRT ….. (a)
⇒P=VnRT ……. (b)
And given that, VP2= constant
Re-writing the above equation –
VP×P= Constant
PV×P= Constant
By placing value from the equation (a)
nRT×P= Constant
Place the value of “P” from the equation (b)
nRT×VnRT= Constant
V(nRT)2= Constant
Since, n and R are constant
⇒VT2= Constant
Now, when volume extends from V to 2V and temperature to T2
⇒2VT22=Constant
⇒VT2= 2VT22
Do cross multiplication and make unknown temperature T2 the subject
T2=V2V×T2
Square and square-root cancel each other on both the sides of the equation.
⇒T2=2T.
Hence, from the given multiple choices – the option C is the correct answer.
Note:
To solve these types of word problems always remember the basic five types of gas laws which deal with how gases behave with respect to the pressure, volume and temperature.
- Boyle’s law
- Charles’ law
- Gay-Lussac’s law
- Combined law
- Ideal Gas law