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Question: During an experiment, a signal from a spaceship reached the ground station in five minutes. What was...

During an experiment, a signal from a spaceship reached the ground station in five minutes. What was the distance of the spaceship from the ground station? The signal travels at the speed of light, that is,3×108m/s3 \times {10^8}m/s.

Explanation

Solution

Here we will proceed by using the formula for speed to find out the distance of the spaceship from the ground station.
Once the light is created, it will continue to travel in a straight line until it collides with something else. Light travels in straight directions, as evidenced by shadows. An item inhibits light from reaching the surface where the shadow is seen.
Depending upon the speed of their motion, objects are said to be in fast or slow motion.

Complete step by step answer:
To calculate the distance of the spaceship from the ground station, we use the formula,
Speed=DistanceTimeSpeed = \dfrac{{Dis\tan ce}}{{Time}}
Given, time taken = 3×108m/s3 \times {10^8}m/s (the signal travels at the speed of light, v=3×108m/sv = 3 \times {10^8}m/s)
Also, we know that time taken by the signal to reach the ground = 5min5min = 5 \times 60\sec $$$$ = 300\sec
Let the distance of the spaceship from the ground station beDD .
We know that, Speed=DistanceTimeSpeed = \dfrac{{Dis\tan ce}}{{Time}}
v=dtv = \dfrac{d}{t}
D=v×tD = v \times t
=3×108×300= 3 \times {10^8} \times 300
=9×1010m= 9 \times {10^{10}}m
So the distance of the spaceship from the ground is=9×1010m = 9 \times {10^{10}}m.

Note: Light from a stationary source travels at 300,000 km/sec300,000{\text{ }}km/sec (186,000 miles/sec)\left( {186,000{\text{ }}miles/sec} \right) Laser beams travel at the speed of light, more than 670670 million miles per hour, making them the fastest thing in the universe.
Speed is a measure of how quickly an object moves from one place to another. It is equal to the distance traveled divided by the time. It is possible to find any of these three values using the other two.