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Question: During a projectile motion if the maximum height equals the horizontal range, then the angle of proj...

During a projectile motion if the maximum height equals the horizontal range, then the angle of projection with the horizontal is:

A

tan–1(1)

B

tan–1(2)

C

tan–1(3)

D

tan–1(4)

Answer

tan–1(4)

Explanation

Solution

Given that

H = R

i.e. uy22 g=2uxuyg\frac { u _ { \mathrm { y } } ^ { 2 } } { 2 \mathrm {~g} } = \frac { 2 \cdot \mathrm { u } _ { \mathrm { x } } \mathrm { u } _ { \mathrm { y } } } { \mathrm { g } }

or uyux=4\frac { u _ { y } } { u _ { x } } = 4 or tan q = 4 or q = tan–1 (4)