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Question: Due to a small magnet intensity at a distance *x* in the end on position is 9 Gauss. What will be th...

Due to a small magnet intensity at a distance x in the end on position is 9 Gauss. What will be the intensity at a distance x2\frac { x } { 2 } on broad side on position

A

9 Gauss

B

4 Gauss

C

36 Gauss

D

4.5 Gauss

Answer

36 Gauss

Explanation

Solution

In C.G.S. Baxial =9=2Mx3B _ { \text {axial } } = 9 = \frac { 2 M } { x ^ { 3 } } .....(i) Bequaterial =M(x2)3=8Mx3B _ { \text {equaterial } } = \frac { M } { \left( \frac { x } { 2 } \right) ^ { 3 } } = \frac { 8 M } { x ^ { 3 } } .....(ii)

From equation (i) and (ii) Bequaterial =36B _ { \text {equaterial } } = 36 Gauss.