Question

Draw the structure of ${{C}_{6}}{{H}_{12}}$.

Answer 1

First find which type of functional group can be present in the compound and then assign the structure. If formula of a hydrocarbon compound is ${{C}_{n}}{{H}_{2n+2}}$, then it is alkane, if the formula is ${{C}_{n}}{{H}_{2n}}$, then it is alkene and if the formula is ${{C}_{n}}{{H}_{2n-2}}$, then the compound is alkyne.

Complete step by step solution:
We are given the molecular formula of the compound and we will now draw its structure.
- We will need to identify the functional group present in the compound in order to draw its structure. See, there are only carbons and hydrogens present in the compound. So, this is a type of a hydrocarbon compound.
- We know that if the molecular formula of the compound is like ${{C}_{n}}{{H}_{2n}}$, then there is a possibility that the compound has an alkene functional group. In our compound, n is 6 and 2n is 12. So, this compound has an alkene functional group.
- Now, we will try to assign this molecule a structure and keep in mind that there is a C-C double bond present in the compound. So, one of the possible structures of this compound is as shown below.

- Now, the double bond in the given stricture is on third and fourth carbon. It can be between any carbons and all those structures of the compounds are acceptable. Geometry at these double bonds can be either cis or trans.

Note: Here another possibility of a structure of ${{C}_{6}}{{H}_{12}}$ is a six member ring without any unsaturation. This compound is called cyclohexane and this does not have any double bond (alkene functional group) in its structure.