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Question: Draw the graph of the equation \( 2x + y = 6 \) . Shade the region bounded by the graph and the coor...

Draw the graph of the equation 2x+y=62x + y = 6 . Shade the region bounded by the graph and the coordinate axis, also find the area.

Explanation

Solution

Hint : To obtain a graph of a linear equation, we first assume some points of either variable(x or y) and then calculate the value of another variable using a given linear equation and then plot these points in x y plane on joining them we will get a graph of a linear equation. Then, find the coordinate of vertices of the triangle formed by a graph of a line and coordinate axis and hence it’s required area.

Complete step-by-step answer :
Given, linear equation is: 2x+y=62x + y = 6
To plot a graph of a linear equation. We first assume some points of either of the variables and then calculate the value of another variable using the given linear equation.
Let x=1,x = 1, substituting it in a given linear equation. We have,
2(1)+y=6 2+y=6 y=62 y=4   2(1) + y = 6 \\\ \Rightarrow 2 + y = 6 \\\ \Rightarrow y = 6 - 2 \\\ \Rightarrow y = 4 \;
Therefore for x=1,x = 1, we have y = 44 .
Let x=2,x = 2, substituting it in a given linear equation. We have,
2(2)+y=6 4+y=6 y=64 y=2   2(2) + y = 6 \\\ \Rightarrow 4 + y = 6 \\\ \Rightarrow y = 6 - 4 \\\ \Rightarrow y = 2 \;
Therefore for x=2,x = 2, we have y = 22 .
Let x=3,x = 3, substituting it in a given linear equation. We have,
2(3)+y=6 6+y=6 y=66 y=0   2(3) + y = 6 \\\ \Rightarrow 6 + y = 6 \\\ \Rightarrow y = 6 - 6 \\\ \Rightarrow y = 0 \;
Therefore for x=3,x = 3, we have y = 00 .
Hence, from above we have a table:

x123
y420

Now, we will plot these points in the xy plane to find a graph of an equation 2x+y=62x + y = 6 .

From the above graph we see that the graph of the linear equation meets the x-axis at (3,0)(3,0) and y-axis at (0,6)(0,6) .
Hence, coordinates of triangle OAB formed by graph of line and coordinate axis are given as:
O(0,0),A(3,0)andD(0,6)O(0,0),\,\,A(3,0)\,\,and\,\,D(0,6) .
Therefore, area of triangle OAB = 12×OA×OD\dfrac{1}{2} \times OA \times OD
ar(ΔOAD)=12×3×6 ar(ΔOAD)=9   \Rightarrow ar(\Delta OAD) = \dfrac{1}{2} \times 3 \times 6 \\\ \Rightarrow ar(\Delta OAD) = 9 \;
Hence, the area of the triangle formed by a graph of a line and coordinate axis is 9squareunit.9\,\,square\,\,unit.

Note : While plotting a graph of any equation. First calculate points very carefully. If all calculated points on plotting a graph do not come on a straight line then it is a hint of mistake. As for linear equations, graphs are always a straight line.