Question

Draw electron dot structure of $C{O_2}$ , ${H_2}O$ , ${F_2}$ , ${N_2}$

Answer 1

We have to know that electron dot designs or Lewis spot equation can be drawn if the atomic recipe of the compound is known. It characterizes the idea of bond and position of particles of the atom, which are associated in the atom. The portrayal of atoms in Lewis electron spot structure is to pay tribute to the American scientist Gilbert Newton Lewis.

Complete answer:
We have to know that a Lewis electron dot formula includes one dab for each valence electron and a component's image. Stages to verbalize the electron spot equation are expressed underneath. Note down a skeletal construction showing a practical holding design through just the component symbols. Get each valence electrons from each iota and throw them into a pretend compartment that we can term an electron pot.
Utilize the $N - A = S$ condition to become more acquainted with the quantity of bonds.
The quantity of valence electrons is equivalent to $N$ .
The quantity of valence electrons in an electron pot is $A$ .
The quantity of electrons partook in the particle rises to $S$ .
Disseminate the electrons from the electron pot to represent the bonds.
Disseminate the remainder of the electrons.
The electron dot structure of $C{O_2}$ , ${H_2}O$ , ${F_2}$ , ${N_2}$ are drawn below.
$O::C::O$
$H..O..H$
$F..F$
$N \vdots \vdots N$

Note:
We have to remember that the Lewis spot structures mirror the electronic constructions of the components, including how the electrons are combined. Lewis structures are a valuable method to sum up certain data about holding and might be considered as electron accounting. In Lewis dab structures each dab addresses an electron.