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Question: Draw a labelled diagram of an electrolytic cell for the extraction of aluminium and the overall reac...

Draw a labelled diagram of an electrolytic cell for the extraction of aluminium and the overall reaction taking place in it.

Explanation

Solution

Aluminum is the most abundant (found in huge amounts) metal on the Earth's crust. It is costly, generally due to the measure of electricity needed in the extraction interaction.
Aluminum metal is called bauxite. The bauxite is decontaminated to create aluminum oxide, a white powder structure in which aluminum can be removed.

Complete step by step answer:
The diagram of the electrolytic cell:

All the reactions taking place in the electrolytic cell is shown below:
Oxidation at anode:
6O212e3O26{O^{2 - }} - 12{e^ - } \to 3{O_2}
Reduction at anode:
4Al3++12e4Al4A{l^{3 + }} + 12{e^ - } \to 4Al
Overall reaction:
2Al2O34Al+3O22A{l_2}{O_3} \to 4Al + 3{O_2}
Following two concepts are there for the reaction taking place during electrolysis:
According to the first theory which is most popular, ionization of alumina occurs firstly:
At cathode:
Al2O3(molten)electrolysis4Al+3O2A{l_2}{O_3}(molten)\xrightarrow{{electrolysis}}4Al + 3{O_2}
Al3++3eAl(l)A{l^{3 + }} + 3{e^ - } \to Al(l)
At anode:
{O2O+2e{O^{2 - }} \to O + 2{e^ - }
O+OO2O + O \to {O_2}
4C+3O22CO+2CO24C + 3{O_2} \to 2CO + 2C{O_2}}
2C+O22CO2C + {O_2} \to 2CO
2CO+O22CO22CO + {O_2} \to 2C{O_2}
Hence, corrosion of graphite rods (anode) occurs and they have to be replaced periodically. For one kg of aluminium produced about 0.50.5 kg of the anode (graphite) is consumed.
2. According to the second concept, ionization of 'Cryolite' occurs firstly on passing electric current.
Na3AlF6(molten.cryolite)electrolysis3NaF+AlF3N{a_3}Al{F_6}(molten. cryolite)\overset {electrolysis} \leftrightarrows 3NaF + Al{F_3}
AlF3electrolysisAl3+3FAl{F_3}\overset {electrolysis} \leftrightarrows A{l^{3 + }}3{F^ - }
At cathode: Al3++3eAl(l)A{l^{3 + }} + 3{e^ - } \to Al(l)
At anode: FF+e{F^ - } \to F + {e^ - }
3C+2Al2O34Al+3CO23C + 2A{l_2}{O_3} \to 4Al + 3C{O_2}
At anode, Al2O3A{l_2}{O_3} is changed into AlF3Al{F_3} and the process of electrolysis continuously goes on when Al2O3A{l_2}{O_3} is again ionised.
The whole reaction may be written in the following way:
2Al2O3+ 3C  4Al + 3CO2A{l_2}{O_3} + {\text{ }}3C{\text{ }} \to {\text{ }}4Al{\text{ }} + {\text{ }}3CO

Note: Molten aluminium thus obtained is collected at the bottom of the cell which is taken out with the help of tap. The aluminium metal obtained by this method is about 99.5%99.5\% pure. The complete process is known as electrometallurgy.