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Question

Physics Question on Motion in a straight line

Diwali rocket is ejecting 50g50\, g of gasses at a velocity of 400m/s400 \,m/s . The accelerating force on the rocket will be

A

22 dyne

B

20 N

C

20 dyne

D

100 N

Answer

20 N

Explanation

Solution

The accelerating force on the rocket
upward thrust =ΔmΔtu=\frac{\Delta m}{\Delta t} \cdot u
Given, ΔmΔt=50×103kg/s,v=400m/s\frac{\Delta m}{\Delta t}=50 \times 10^{-3} kg / s ,\, v=400\, m / s
So, accelerating force =50×103×400=50 \times 10^{-3} \times 400
=20N=20\, N