Question
Question: Divide the line segment of \( {\rm{10}}\;{\rm{cm}} \) in the ratio \( 3:2 \) ....
Divide the line segment of 10cm in the ratio 3:2 .
Solution
Hint : To solve this problem, we will draw a line segment of required length and then we will draw another ray which makes an acute angle with the line segment. According to the ratio given, we will divide this ray into a number of parts by drawing the equal arcs. After that we join the last point on the ray with the end point of the given segment. Now we can find the number of divisions according to the ratios given in the question.
Complete step-by-step answer :
We have the line of 10cm. We will assume it as AB .
In order to divide the line in the ratio 3:2 we will draw a line segment AB . Next, we will draw a ray AX such that this ray is forming an acute angle with line AB .That is the angle should be less than 90∘ .This can be shown as:
Now with the help of compass we will 5 mark points A1 , A2 , A3 , A4 and A5 on the ray AX , as the given ratio is 3:2 . Hence the total number of divisions we require is equal to 5. We will draw these points such that AA1=A1A2=A2A3=A3A4=A4A5 . This can be done by drawing the arcs that are equal. This can be shown as:
Now, we will join A5 with B .Since A3 is the third point, we will draw line passing through point A3 and intersecting line AB such that this line is parallel to the line A5B .
Hence the line segment is divided into 3:2 . When we will measure the length of AC it will come out to be 6cm and the length of line BC will come out to be 4cm .
Note : This question can be solved by the analytical and the constructional method. Here, we are using the constructional method. We can also divide the line segment from the concept of ratio and proportion. Since the ratio is given as 3:2 and we know that whenever we have given ratio as m:n we can simply use the formula m+n(m×x)+(n×x) where x denotes the length of line segment and m and n denotes the terms which are in ratios.