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Question

Question: Divide the line segment of \( {\rm{10}}\;{\rm{cm}} \) in the ratio \( 3:2 \) ....

Divide the line segment of 10  cm{\rm{10}}\;{\rm{cm}} in the ratio 3:23:2 .

Explanation

Solution

Hint : To solve this problem, we will draw a line segment of required length and then we will draw another ray which makes an acute angle with the line segment. According to the ratio given, we will divide this ray into a number of parts by drawing the equal arcs. After that we join the last point on the ray with the end point of the given segment. Now we can find the number of divisions according to the ratios given in the question.

Complete step-by-step answer :
We have the line of 10  cm{\rm{10}}\;{\rm{cm}}. We will assume it as ABAB .
In order to divide the line in the ratio 3:23:2 we will draw a line segment ABAB . Next, we will draw a ray AXAX such that this ray is forming an acute angle with line ABAB .That is the angle should be less than 90{90^ \circ } .This can be shown as:

Now with the help of compass we will 5 mark points A1{A_1} , A2{A_2} , A3{A_3} , A4{A_4} and A5{A_5} on the ray AXAX , as the given ratio is 3:23:2 . Hence the total number of divisions we require is equal to 5. We will draw these points such that AA1=A1A2=A2A3=A3A4=A4A5A{A_1} = {A_1}{A_2} = {A_2}{A_3} = {A_3}{A_4} = {A_4}{A_5} . This can be done by drawing the arcs that are equal. This can be shown as:

Now, we will join A5{A_5} with BB .Since A3{A_3} is the third point, we will draw line passing through point A3{A_3} and intersecting line ABAB such that this line is parallel to the line A5B{A_5}B .

Hence the line segment is divided into 3:23:2 . When we will measure the length of ACAC it will come out to be 6  cm{\rm{6}}\;{\rm{cm}} and the length of line BCBC will come out to be 4  cm{\rm{4}}\;{\rm{cm}} .

Note : This question can be solved by the analytical and the constructional method. Here, we are using the constructional method. We can also divide the line segment from the concept of ratio and proportion. Since the ratio is given as 3:23:2 and we know that whenever we have given ratio as m:nm:n we can simply use the formula (m×x)+(n×x)m+n\dfrac{{\left( {m \times x} \right) + \left( {n \times x} \right)}}{{m + n}} where xx denotes the length of line segment and mm and nn denotes the terms which are in ratios.