Question

Distance between successive compression and rarefaction is $1 \,m$ and velocity of sound is $360 \,ms^{-1}$. Find frequency :

• A. 180 Hz
• B. 45 Hz
• C. 120 Hz
• D. 90 Hz

Answer 1

Answer: (A)

180 Hz

Answer 2

$\lambda=2 d=2 m$ $v=\frac{\nu}{\lambda}=\frac{360 \,ms ^{-1}}{2 \,m }=180 \,Hz$ Reason : As it can be understood from the figure, distance between successive compressions and rarefactions is one half of the wavelength.