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Question

Question: Distance between parallel planes \(2x - 2y + z + 3 = 0\)and \(4x - 4y + 2z + 5 = 0\) is...

Distance between parallel planes 2x2y+z+3=02x - 2y + z + 3 = 0and 4x4y+2z+5=04x - 4y + 2z + 5 = 0 is

A

23\frac{2}{3}

B

13\frac{1}{3}

C

16\frac{1}{6}

D

2

Answer

16\frac{1}{6}

Explanation

Solution

The required distance is given by

322+22+12542+42+22=156=16\left| \frac { 3 } { \sqrt { 2 ^ { 2 } + 2 ^ { 2 } + 1 ^ { 2 } } } - \frac { 5 } { \sqrt { 4 ^ { 2 } + 4 ^ { 2 } + 2 ^ { 2 } } } \right| = \left| 1 - \frac { 5 } { 6 } \right| = \frac { 1 } { 6 }.