Question

Dissolving $120 \,g$ of a compound of (mol. wt. $60$) in $1000 \,g$ of water gave a solution of density $1.12 \,g/mL$. The molarity of the solution is :

• A. 1.00 M
• B. 2.00 M
• C. 2.50 M
• D. 4.00 M

Answer 1

Answer: (B)

2.00 M

Answer 2

Molarity of solution =$\frac{\left(\frac{120}{60}\right)}{\frac{1120}{1.12}\times\frac{1}{100}}$
$= 2 \,M$