Solveeit Logo
Login

Question

Question: Dissociation of water takes place in two steps: \[H_{2}O \rightarrow H + OH;\Delta H = + 497.8kJ\] ...

Dissociation of water takes place in two steps:

H2O→H+OH;ΔH=+497.8kJH_{2}O \rightarrow H + OH;\Delta H = + 497.8kJ

OH→H+O;ΔH=428.5kJOH \rightarrow H + O;\Delta H = 428.5kJ

What is the bond energy of O – H bond?

A

463.15kJmol−1463.15kJmol^{- 1}

B

428.5kJmol−1428.5kJmol^{- 1}

C

69.3kJmol−169.3kJmol^{- 1}

D

926.3kJmol−1926.3kJmol^{- 1}

Answer

463.15kJmol−1463.15kJmol^{- 1}

Explanation

Solution

: Average of two bond dissociation energies:

497.8+428.52=463.15kJmol−1\frac{497.8 + 428.5}{2} = 463.15kJmol^{- 1}