Question
Mathematics Question on limits and derivatives
x→1lim [(x2−x−14x−1−x31−3x+x2)−1+3(x3−x−1x4−1)] is
A
2
B
3
C
4
D
1
Answer
3
Explanation
Solution
Given limit can be written as, x→1lim [(x3−14x−1−x31−3x+x2)−1+x4−13x(x4−1)] =x→1lim [(x3−14x+1−3x+x2)−1+3x] =x→1lim [x2+x+1x3−1+3x] =x→1lim(x−1+3x)=3