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Question

Mathematics Question on Measures of Dispersion

limt0sin(t2)tsin(5t) is equal to\displaystyle\lim_{t\rightarrow0}\frac{sin(t^2)}{tsin(5t)} \ is\ equal\ to

A

5

B

25

C

125\frac{1}{25}

D

15\frac{1}{5}

E

0

Answer

15\frac{1}{5}

Explanation

Solution

The correct option is (D) : 15\frac{1}{5}