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Question

Mathematics Question on Continuity and differentiability

Discuss the continuity of the following functions.
(a) f(x)=sinx+cosx
(b) f(x)=sinx−cosx
(c) f(x)=sinx×\timescosx

Answer

It is known that if g and h are two continuous functions, then
g+h,g-h and g.h are also continuous.
It has to proved first that g(x)=sinx and h(x)=cos x are continuous functions.
Let g(x)=sinx It is evident that g(x)=sinx is defined for every real number.
Let c be a real number. Put x=c+h
If x\rightarrowc,then h\rightarrow0
g(c)=sinc
limxcg(x)\lim_{x\rightarrow c}g(x)=limxcsinx\lim_{x\rightarrow c}sin\,x
=limh0sin(c+h)\lim_{h\rightarrow 0}sin(c+h)
=limh0\lim_{h\rightarrow 0}[sin c cos h+cos c sin h]
=sin c cos 0+cos c sin 0
=sin c+0=sin c
limxcg(x)\lim_{x\rightarrow c}g(x)=g(c)g(c)
Therefore, g is a continuous function.
Let h(x)=cos x It is evident that h(x)=cosx is defined for every real number.
Let c be a real number. Put x=c+h
If x\rightarrowc, then h\rightarrow0
h(c)=cosc
limxc\lim_{x\rightarrow c}h(x)=limxc\lim_{x\rightarrow c} cos x
=limh0\lim_{h\rightarrow 0}cos(c+h)
=limh0\lim_{h\rightarrow 0}[cosccosh-sincsinh]
=limh0\lim_{h\rightarrow 0}cos c cos h-limh0\lim_{h\rightarrow 0} sin c sin h
=cos c cos 0-sin csin 0
=cos c×\times1-sin c×\times0
=cos c
limxc\lim_{x\rightarrow c}h(x)=h(c)
Therefore, h is a continuous function.
Therefore, it can be concluded that
(a)f(x)=g(x)+h(x)=sinx+cosx is a continuous function
(b)f(x)=g(x)-h(x)=sinx−cosx is a continuous function
(c)f(x)=g(x)×h(x)=sinx×cosx is a continuous function