Question

Dipole moment of $HCl =1.03\, D , HI =0.38 \,D$. Bond length of $HCl =1.3\,�$and $HI =1.6 \,�$. The ratio of fraction of electric charge, $\delta$, existing on each atom in $HCl$ and $HI$ is

• A. 12:01
• B. 2.7 : 1
• C. 3.3 : 1
• D. 01:03.3

Answer 1

Answer: (C)

3.3 : 1

Answer 2

Dipole moment,
$(\mu)=\delta \times d$
where, $\delta=$ magnitude of electric charge
$d=$ distance between particles (or bond length)
$\therefore \delta=\frac{\mu}{d}$
or $\frac{\delta_{H C I}}{\delta_{H I}}=\frac{\mu_{H C I}}{d_{H C I}} \times \frac{d_{H I}}{\mu_{H I}}$
$=\frac{1.03 \times 1.6}{1.3 \times 0.38}$
$=3.3: 1$