Question
Question: Dimensions of permeability are...
Dimensions of permeability are
A
A−2M1L1T−2
B
MLT−2
C
ML0T−1
D
A−1MLT2
Answer
A−2M1L1T−2
Explanation
Solution
F=4πμ0r2I1I2l ⇒ μ0=[F][A]−2=[MLT−2A−2]
Dimensions of permeability are
A−2M1L1T−2
MLT−2
ML0T−1
A−1MLT2
A−2M1L1T−2
F=4πμ0r2I1I2l ⇒ μ0=[F][A]−2=[MLT−2A−2]