Solveeit Logo
Login

Question

Question: Dimensions of kinetic energy are...

Dimensions of kinetic energy are

A

ML2T−2ML^{2}T^{- 2}

B

M2LT−1M^{2}LT^{- 1}

C

ML2T−1ML^{2}T^{- 1}

D

ML3T−1ML^{3}T^{- 1}

Answer

ML2T−2ML^{2}T^{- 2}

Explanation

Solution

Kinetic energy

= 12mv2=M[LT−1]2=[ML2T−2]\frac{1}{2}mv^{2} = M\lbrack LT^{- 1}\rbrack^{2} = \lbrack ML^{2}T^{- 2}\rbrack