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Question

Physics Question on Dimensional Analysis

Dimensions of LRCV\frac{L}{RCV} are

A

[A1][A^{-1}]

B

[A2][A^{-2}]

C

[A][A]

D

[A2][{{A}^{2}}]

Answer

[A1][A^{-1}]

Explanation

Solution

LR\frac{L}{R} has the dimensions of time. Because LR\frac{L}{R} is the time constant of LRL-R circuit.
[LR]=[T]\therefore \left[\frac{L}{R}\right]=[ T ]
Charge == Capacitance ×\times Potential difference
Q=CVQ=C V
and [Q]=[AT]{[Q]=[A T]}
[LRCV]=[LQ]\therefore \left[\frac{L}{R C V}\right]=\left[\frac{L}{Q}\right]
=[TAT]=\left[\frac{T}{A T}\right]
[LRCV]=[A1]\left[\frac{L}{R C V}\right]=\left[A^{-1}\right]

Therefore, the correct option is (A): [A1][A^{-1}]