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Question

Physics Question on Units and measurement

Dimensional formula of self inductance is

A

[MLT2A2][MLT^{-2}A^{-2}]

B

[ML2T1A2][ML^2T^{-1}A^{-2}]

C

[ML2T2A2][ML^2T^{-2}A^{-2}]

D

[ML2T2A1][ML^2T^{-2}A^{-1}]

Answer

[ML2T2A2][ML^2T^{-2}A^{-2}]

Explanation

Solution

Induced emf ε=LdIdt|\varepsilon |=L\frac{dI}{dt}
where LL is the self inductance and dIdt\frac{dI}{dt} is the rate of change of current.
\therefore Dimensional formula of L=εdIdtL=\frac{|\varepsilon |}{\frac{dI}{dt}}
=[ML2T3A1][AT1]=\frac{[ML^2T^{-3}A^{-1}]}{[AT^{-1}]}
=[ML2A2T2]=[ML^2A^{-2}T^{-2}]