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Question

Question: Dimensional formula of magnetic flux is...

Dimensional formula of magnetic flux is

A

ML2T−2A−1ML^{2}T^{- 2}A^{- 1}

B

ML0T−2A−2ML^{0}T^{- 2}A^{- 2}

C

M0L−2T−2A−3M^{0}L^{- 2}T^{- 2}A^{- 3}

D

ML2T−2A3ML^{2}T^{- 2}A^{3}

Answer

ML2T−2A−1ML^{2}T^{- 2}A^{- 1}

Explanation

Solution

φ=BA=FI×LA=[MLT−2][L2][A][L]=[ML2T−2A−1]\varphi = BA = \frac{F}{I \times L}A = \frac{\lbrack MLT^{- 2}\rbrack\lbrack L^{2}\rbrack}{\lbrack A\rbrack\lbrack L\rbrack} = \lbrack ML^{2}T^{- 2}A^{- 1}\rbrack