Question

Dimensional formula for the gravitational constant is-

• A. [M^–1L³T^–2]
• B. [M^–1L²T^–3]
• C. [M^–1LT^–2]
• D. [M^–2L³T^–1]

Answer 1

Answer: (A)

$M^–1L³T^–2$

Answer 2

G = $\frac{Fr^{2}}{m_{1}m_{2}}$