Question
Mathematics Question on Continuity and differentiability
Differentiate the functions with respect to x.
cos x3.sin2(x5)
Answer
The given function is cos x3 . sin2(x5)
dxd[cos x3. sin2(x5)] = sin2(x5) . dxd(cos x3) + cos x3 . dxd[sin2(x5)]
= sin2(x5) . (- sin x3) . dxd(x3) + cos x3 . 2 sin (x5) . dxd(sin x5)
= -sin x3 sin2(x5) . 3x2 + 2 sin x5 cos x3 . cos x5. dxd(x5)
= -3x2 sin x3 . sin2(x5) + 2 sin x5 cos x5 cos x3.5x4
= 10x4 sin x5 cos x5 cos x3 - 3x2 sinx3 cosx3 sin2(x5)