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Question

Mathematics Question on Continuity and differentiability

Differentiate the functions with respect to x.
cos x3.sin2(x5)cos\ x^3.sin^2(x^5)

Answer

The given function is cos x3 . sin2(x5)

ddx\frac {d}{dx}[cos x3. sin2(x5)] = sin2(x5) . ddx\frac {d}{dx}(cos x3) + cos x3 . ddx\frac {d}{dx}[sin2(x5)]
= sin2(x5) . (- sin x3) . ddx\frac {d}{dx}(x3) + cos x3 . 2 sin (x5) . ddx\frac {d}{dx}(sin x5)
= -sin x3 sin2(x5) . 3x2 + 2 sin x5 cos x3 . cos x5. ddx\frac {d}{dx}(x5)
= -3x2 sin x3 . sin2(x5) + 2 sin x5 cos x5 cos x3.5x4
= 10x4 sin x5 cos x5 cos x3 - 3x2 sinx3 cosx3 sin2(x5)