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Question

Question: Differentiate \(\left( {{{\sin }^2}x} \right)\) with respect to \(x\)....

Differentiate (sin2x)\left( {{{\sin }^2}x} \right) with respect to xx.

Explanation

Solution

In the given problem, we are required to differentiate (sin2x)\left( {{{\sin }^2}x} \right) with respect to x. Since, (sin2x)\left( {{{\sin }^2}x} \right) is a composite function, so we will have to apply chain rule of differentiation in the process of differentiating (sin2x)\left( {{{\sin }^2}x} \right) . So, differentiation of (sin2x)\left( {{{\sin }^2}x} \right) with respect to x will be done layer by layer using the chain rule of differentiation. Also the derivative of sin(x)\sin (x)with respect to xx must be remembered.

Complete step by step answer:
So, Derivative of (sin2x)\left( {{{\sin }^2}x} \right) with respect to xxcan be calculated as ddx(sin2x)\dfrac{d}{{dx}}\left( {{{\sin }^2}x} \right) .
Now, ddx(sin2x)\dfrac{d}{{dx}}\left( {{{\sin }^2}x} \right)
Taking the power outside the bracket in order to apply chain rule of differentiation.
ddx[(sinx)2]\dfrac{d}{{dx}}\left[ {{{\left( {\sin x} \right)}^2}} \right]
Now, Let us assume u=sin(x)u = \sin (x). So substituting sin(x)\sin (x) as uu, we get,
ddx[u]2=2ududx\dfrac{d}{{dx}}{\left[ u \right]^2} = 2u\dfrac{{du}}{{dx}}

Now, putting back uu as sin(x)\sin (x), we get,
2sinxd(sinx)dx2\sin x\dfrac{{d\left( {\sin x} \right)}}{{dx}} because dudx=d(sinx)dx\dfrac{{du}}{{dx}} = \dfrac{{d(\sin x)}}{{dx}}
Now, we know that the derivative of sinx\sin x with respect to xx is cosx\cos x. So, ddx(sinx)=cosx\dfrac{d}{{dx}}\left( {\sin x} \right) = \cos x.
So, Substituting the equivalent expression of ddx(sinx)\dfrac{d}{{dx}}\left( {\sin x} \right), we get,
2sinx(cosx)2\sin x\left( {\cos x} \right)
Now, we know the double angle formula for sine function as sin2x=2sinxcosx\sin 2x = 2\sin x\cos x. So, we get sin2x\sin 2x.

So, the derivative of (sin2x)\left( {{{\sin }^2}x} \right) with respect to xx is sin2x\sin 2x.

Note: The derivatives of basic trigonometric functions must be learned by the heart in order to find derivatives of complex composite functions using the chain rule of differentiation. The chain rule of differentiation involves differentiating a composite by introducing new unknowns to ease the process and examine the behavior of function layer by layer. The answer to the problem can also be 2sinx(cosx)2\sin x\left( {\cos x} \right), but it is better to use the double angle formula of the sine function and give a precise final answer.