Question

Dielectric constant of pure water is 81. Its permittivity will be

• A. $7.12 \times 10^{- 10}MKS$ units
• B. $8.86 \times 10^{- 12}MKS$ units
• C. $1.02 \times 10^{13}\mspace{6mu} MKS$ units
• D. Cannot be calculated

Answer 1

Answer: (A)

$7.12 \times 10^{- 10}MKS$ units

Answer 2

$\varepsilon = K\varepsilon_{0} = 81 \times 8.854 \times 10^{- 12} = 7.17 \times 10^{- 10}MKSunits$