Question

Dick is thrice as old as Tom and Harry is twice as old as Dick. If Dick's age is 1 year less than the average age of all three, then Harry's age, in years, is

Answer 1

Let the age of Tom be $t$.
Ages of Dick and Harry are $3t$ and $6t$ respectively.
Given, $3t = \frac{t+3t+6t}{3}-1 ⇒ 9t \Rightarrow10t-3 ⇒ t=3$
Age of Harry =$6×3 = 18$