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Question

Physics Question on Wave optics

Diameter of 8th8^{th} dark ring in Newton's rings system viewed normally in reflected light of wavelength 5000A˚5000 \mathring A is 4 mm. Radius of curvature of convex surface in contact with the glass plate is

A

1.5 m

B

1 m

C

0.5 m

D

2 m

Answer

1 m

Explanation

Solution

Here, λ=5000A˚,Dn=4mm\lambda = 5000 \mathring A , D_n = 4 \: mm
As Dn2=4nRλD_n^2 = 4n \: R \lambda
or R=Dn24nλ=(4×103)24×8×5000×1010=1mR = \frac{ D_n^2 }{4 n \lambda} = \frac{( 4 \times 10^{-3})^2}{4 \times 8 \times 5000 \times 10^{-10} } = 1 m