Question

Diagram shows a parallel plate capacitor having surface charge density σ C/m² with its one plate at origin and other plate at x = 3 cm. The potential difference between points A and B is –

• A. $\frac { \sigma } { \epsilon _ { 0 } }$ × 2 × 10^–2 volt
• B. ×1×10^–2 volt
• C. $\frac { \sigma } { \epsilon _ { 0 } }$ × 1 × 10^–2 volt
• D. × 2 volts

Answer 1

Answer: (C)

$\frac { \sigma } { \epsilon _ { 0 } }$ × 1 × 10^–2 volt

Answer 2

V_A – V_B = = E₀ =

= $\frac { \sigma } { \epsilon _ { 0 } }$ × (1 cm) = $\frac { \sigma } { \epsilon _ { 0 } }$ × 1 × 10^–2 volts