Solveeit Logo

Question

Question: Determine the value of \( {C_p},{C_v} \) and \( \gamma \) for a monatomic, diatomic and polyatomic g...

Determine the value of Cp,Cv{C_p},{C_v} and γ\gamma for a monatomic, diatomic and polyatomic gas.

Explanation

Solution

In a thermodynamic system, Cp{C_p} is the amount of heat energy absorbed or released by a unit mass of a given substance with the change in temperature at a constant pressure. Cv{C_v} is the amount of heat energy transferred between a system and its surroundings at a constant volume. γ\gamma is the ratio of Cp{C_p} and Cv{C_v}

Complete answer:
The degree of freedom of a molecule will affect the value of all the specific heat constants.
For any molecule the degrees of freedom is given by the equation:
f=3Nmf = 3N - m
Where f is the degree of freedom
N is the number of particles in the given system/molecule
m is the number of constraints.
So for the given type of molecules we can say that:

Type of moleculeDegrees of freedom
Monoatomic molecule3 (N=1, m=0)
Diatomic molecule5 (N=2, m=1)
Polyatomic molecule>6

Now we can say that the specific heat constants are related to the degree of freedom by the following equations:
Cp=R(1+12f)\Rightarrow {C_p} = R(1 + \dfrac{1}{2}f)
Cv=12f×R\Rightarrow {C_v} = \dfrac{1}{2}f \times R
γ=1+2f\Rightarrow \gamma = 1 + \dfrac{2}{f}
Therefore we can substitute the values of f in the equations and obtain the value of all the constants for monoatomic, diatomic and polyatomic gas.

Type of Gas moleculeDegree of freedom fCp{C_p}Cv{C_v}γ\gamma
Monoatomic352R\dfrac{5}{2}R32R\dfrac{3}{2}R53\dfrac{5}{3}
Diatomic572R\dfrac{7}{2}R52R\dfrac{5}{2}R75\dfrac{7}{5}
Triatomic (A case of polyatomic)7 (where N=3 and m=2)92R\dfrac{9}{2}R72R\dfrac{7}{2}R97\dfrac{9}{7}

Note:
For gas with molecules having higher numbers of atomicity, the degree of freedom would vary even more because there are a large number of arrangements that are possible. This will mean that there will be more degrees of freedom with each type of molecule. Thus for such types of gases a known degree of freedom can be used to figure out the specific molar heats and their ratios, which will always be decreasing with increasing atomicity of the molecule.