Question
Question: Determine the value of \( {C_p},{C_v} \) and \( \gamma \) for a monatomic, diatomic and polyatomic g...
Determine the value of Cp,Cv and γ for a monatomic, diatomic and polyatomic gas.
Solution
In a thermodynamic system, Cp is the amount of heat energy absorbed or released by a unit mass of a given substance with the change in temperature at a constant pressure. Cv is the amount of heat energy transferred between a system and its surroundings at a constant volume. γ is the ratio of Cp and Cv
Complete answer:
The degree of freedom of a molecule will affect the value of all the specific heat constants.
For any molecule the degrees of freedom is given by the equation:
f=3N−m
Where f is the degree of freedom
N is the number of particles in the given system/molecule
m is the number of constraints.
So for the given type of molecules we can say that:
Type of molecule | Degrees of freedom |
---|---|
Monoatomic molecule | 3 (N=1, m=0) |
Diatomic molecule | 5 (N=2, m=1) |
Polyatomic molecule | >6 |
Now we can say that the specific heat constants are related to the degree of freedom by the following equations:
⇒Cp=R(1+21f)
⇒Cv=21f×R
⇒γ=1+f2
Therefore we can substitute the values of f in the equations and obtain the value of all the constants for monoatomic, diatomic and polyatomic gas.
Type of Gas molecule | Degree of freedom f | Cp | Cv | γ |
---|---|---|---|---|
Monoatomic | 3 | 25R | 23R | 35 |
Diatomic | 5 | 27R | 25R | 57 |
Triatomic (A case of polyatomic) | 7 (where N=3 and m=2) | 29R | 27R | 79 |
Note:
For gas with molecules having higher numbers of atomicity, the degree of freedom would vary even more because there are a large number of arrangements that are possible. This will mean that there will be more degrees of freedom with each type of molecule. Thus for such types of gases a known degree of freedom can be used to figure out the specific molar heats and their ratios, which will always be decreasing with increasing atomicity of the molecule.